Wednesday, May 6, 2015
Who Columns In Oracle Apps
Creation of New User:
1)Open the internet Explorer connect to Oracle Applications
2)Enter the User Name :OPERATIONS
Password :WELCOME
3)Select the Responsibility called 'System Administrator'
4)Open the User form.
Security => User =>Define
5)Enter User Name and Password attach the Responsibilities whatever we required
for ex System Administrator
Application Developer
6)Exit from the Appication
File => Exit Oracle Applications
7)Connect to Oracle apps enter new user name password system will shows the message
like 'Password Has Expired'
8)Enter the New Password Press Ok Button
Short Cuts:
===========
1)To Query All the Records Press CTRL+F11
2)To Query Specific Records
i)Open the Form
ii)Press F11 (Form will comes into Query mode)
iii)Enter Search Criteria in any field
iV)Press CTRL+F11
3)To Close Form = F4
5)To Save the Records CTRL+S
Effective Date From and To:
===========================
In most of the Oracle Application forms we will find two field like
Effective Date From
Effective Date To
In some of the forms once we create records and save. We can not delete from database
that time we can go for Disable/Enable the record by using these two fields
Finding Table NameS/Column Names:
=================================
1)Help => Record History which will shows the Table Name
2)Help Menu=>Diagnastics=>Examine=>Enter the Password(APPS)=>We can find the Column Name
WHO Columns:
=============
WHO Column Will be used to find out the History of the record
we can find from front End Also
Help=>Record History
CREATED_BY - Which User has created the Record(Userid)
CREATION_DATE - at what time user has created (SYSDATE)
LAST_UPATED_BY -Which User has updated recentley(UserID)
LAST_UPDATE_DATE -at what time user has Updated (SYSDATE)
LAST_LOGON_DATE - At what time user last Login Time
Find the Login UserName:
==========================
Help Menu=>About Oracle Applications
1)Open the internet Explorer connect to Oracle Applications
2)Enter the User Name :OPERATIONS
Password :WELCOME
3)Select the Responsibility called 'System Administrator'
4)Open the User form.
Security => User =>Define
5)Enter User Name and Password attach the Responsibilities whatever we required
for ex System Administrator
Application Developer
6)Exit from the Appication
File => Exit Oracle Applications
7)Connect to Oracle apps enter new user name password system will shows the message
like 'Password Has Expired'
8)Enter the New Password Press Ok Button
Short Cuts:
===========
1)To Query All the Records Press CTRL+F11
2)To Query Specific Records
i)Open the Form
ii)Press F11 (Form will comes into Query mode)
iii)Enter Search Criteria in any field
iV)Press CTRL+F11
3)To Close Form = F4
5)To Save the Records CTRL+S
Effective Date From and To:
===========================
In most of the Oracle Application forms we will find two field like
Effective Date From
Effective Date To
In some of the forms once we create records and save. We can not delete from database
that time we can go for Disable/Enable the record by using these two fields
Finding Table NameS/Column Names:
=================================
1)Help => Record History which will shows the Table Name
2)Help Menu=>Diagnastics=>Examine=>Enter the Password(APPS)=>We can find the Column Name
WHO Columns:
=============
WHO Column Will be used to find out the History of the record
we can find from front End Also
Help=>Record History
CREATED_BY - Which User has created the Record(Userid)
CREATION_DATE - at what time user has created (SYSDATE)
LAST_UPATED_BY -Which User has updated recentley(UserID)
LAST_UPDATE_DATE -at what time user has Updated (SYSDATE)
LAST_LOGON_DATE - At what time user last Login Time
Find the Login UserName:
==========================
Help Menu=>About Oracle Applications
Wednesday, April 29, 2015
Oracle SQL Loader
SIMPLE CONTROL FILE USING SINGLE DATA FILE
1.create table in scott and give grant to apps then create synonym in app
create table emp3(empno number(10),ename varchar2(10),job varchar2(10),sal number(10,2))
SQL> /
Table created.
SQL> grant all on emp3 to apps;
Grant succeeded.
SQL> conn apps/apps@prod
Connected.
SQL> create public synonym emp3 for scott.emp3;
Synonym created.
SQL> desc emp3;
Name Null? Type
----------------------------------------------------- -------- ------------------------------------
EMPNO NUMBER(10)
ENAME VARCHAR2(10)
JOB VARCHAR2(10)
SAL NUMBER(10,2)
2.data file
3.control file
4.RUN CMD THEN GIVE COMMAND AS
D:\ORACLE\PRODDB\8.1.7\BIN> SQLLDR APPS/APPS@PROD
CONTROL =D:\DATA\EMP3.CTL
5.GOTO SQL PROMPT THEN VIEW THE OUT PUT:
SQL> SELECT * FROM EMP3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
100 'smith' 'mgr' 7000
200 'ramu' 'clerk' 4000
300 'raju' 'act' 6000
SQL>
Multiple Data Files Into Single Database table using single control file
1.Create second data file:
111,'RAVI','MGR',7000
222,'KIRAN','CLERK',4000
333,'CHANDRA','ASTMGR',10000
save this as EMP4.DAT in same directory
2.Goto control file then assign this file as second infile to control file
controlfile:
load data
infile 'd:\data\emp3.dat'
infile 'd:\data\EMP4.dat'
insert into table emp3
fields terminated by ','
(empno
,ename
,job
,sal
)
3.Again run cmd as above
4.goto backend view data
SQL> select * from emp3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
111 'RAVI' 'MGR' 7000
222 'KIRAN' 'CLERK' 4000
333 'CHANDRA' 'ASTMGR' 10000
100 'smith' 'mgr' 7000
200 'ramu' 'clerk' 4000
300 'raju' 'act' 6000
6 rows selected.
Control file using sql functions
1) Assign the sql functions to the columns in Control file
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno "S1.NEXTVAL",
ename POSITION(4:7) "UPPER(:ENAME)",
job POSITION(8:10) "INITCAP(:JOB)",
sal POSITION(11:14) "NVL(:SAL*10,0)"
)
into table emp4 when projno!=' '
(
empno "S1.NEXTVAL",
ename POSITION(4:7) "UPPER(:ENAME)",
job POSITION(8:10) "INITCAP(:JOB)",
sal POSITION(11:14) "NVL(:SAL*10,0)",
projno POSITION(15:17)
)
2
AGAIN RUN CMD:
2. THEN VIEW THE DATA IN BACK END AS:
SQL> SELECT * FROM EMP3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
192 RAVI Mgr 70000
193 RAJU Mgr 40000
194 CHAN Mgr 10000
186 RAVI Mgr 70000
187 RAJU Mgr 40000
188 CHAN Mgr 10000
6 rows selected.
SQL> SELECT * FROM EMP4;
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
195 RAVI Mgr 70000 120
196 RAJU Mgr 40000 121
197 CHAN Mgr 10000 122
189 RAVI Mgr 70000 120
190 RAJU Mgr 40000 121
191 CHAN Mgr 10000 122
6 rows selected.
Using where clause in control file to update data into multiple tables
Multiple data files and Multiple tables
1.Create 2 tables and 2 data files
first is emp3 which is already created
Now created second table
CREATE TABLE EMP4 AS SELECT * FROM EMP3 WHERE 1=2
1.1ALTER TABLE EMP4 ADD PROJNO NUMBER; /*for additing additional column for secondtable */
SQL> DESC EMP4;
Name Null? Type
----------------------------------------------------- -------- ----------------------
EMPNO NUMBER(10)
ENAME VARCHAR2(10)
JOB VARCHAR2(10)
SAL NUMBER(10,2)
PROJNO NUMBER
SQL> GRANT ALL ON EMP4 TO APPS;
Grant succeeded.
SQL> CONN APPS/APPS@PROD
Connected.
SQL> CREATE PUBLIC SYNONYM EMP4 FOR SCOTT.EMP4;
Synonym created.
2.create datafile as emp3
111RAVIMGR7000120
222RAJUMGR4000121
333CHANMGR1000122
3.create data file as emp4
111RAVIMGR7000120
222RAJUMGR4000121
333CHANMGR1000122
4.create control file as
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno POSITION(1:3),
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14)
)
into table emp4 when projno!=' '
(empno POSITION(1:3),
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14),
projno POSITION(15:17)
)
save;
5.run cmd as usual
6.view the output in backend
SQL> select * from emp3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
111 RAVI MGR 7000
222 RAJU MGR 4000
333 CHAN MGR 1000
111 RAVI MGR 7000
222 RAJU MGR 4000
333 CHAN MGR 1000
6 rows selected.
SQL> select * from emp4;
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
111 RAVI MGR 7000 120
222 RAJU MGR 4000 121
333 CHAN MGR 1000 122
111 RAVI MGR 7000 120
222 RAJU MGR 4000 121
333 CHAN MGR 1000 122
6 rows selected.
Using commit in control files for each 10 records
1 .we will create a sequence as s1
SQL> CONN SCOTT/TIGER@PROD
Connected.
SQL> CREATE SEQUENCE S1 INCREMENT BY 1 START WITH 100;
Sequence created.
SQL> conn apps/apps@prod
Connected.
2.then we will create control file as
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14)
)
into table emp4 when projno!=' '
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14),
projno POSITION(15:17)
)
then save;
4.then run as usual.
5 .view the data from backend as
SQL> /
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
106 RAVI MGR 7000
107 RAJU MGR 4000
108 CHAN MGR 1000
100 RAVI MGR 7000
101 RAJU MGR 4000
102 CHAN MGR 1000
6 rows selected.
SQL> ed
Wrote file afiedt.buf
1* select * from emp4
SQL> /
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
109 RAVI MGR 7000 120
110 RAJU MGR 4000 121
111 CHAN MGR 1000 122
103 RAVI MGR 7000 120
104 RAJU MGR 4000 121
105 CHAN MGR 1000 122
6 rows selected
To Create Commit Statement in cmd Prompt
GOTO RUN CMD AND GIVE COMMAND AS TO FOR EVERY 2 RECORDS
TO SKIP RECORDS FROM LOADING USING SKIP KEYWORDS IN CONTROL FILE
GO TO RUN CMD:THEN GIVE THE COMMAND AS:
Goto backend and view the data:
SQL> SELECT * FROM EMP3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
148 CHAN MGR 1000
TO SKIP COLUMNS IN CONTROL FILES USING FILLER KEYWORD
Use the FILLER keyword in control files as:
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job filler,
sal POSITION(11:14)
)
into table emp4 when projno!=' '
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14),
projno POSITION(15:17)
)
Then goto run cmd give the command as usual:
Then view the data in backend :
SQL> select * from emp3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
150 RAVI 7000
151 RAJU 4000
152 CHAN 1000
156 RAVI 7000
157 RAJU 4000
158 CHAN 1000
6 rows selected.
SQL> select * from emp4;
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
153 RAVI MGR 7000 120
154 RAJU MGR 4000 121
155 CHAN MGR 1000 122
159 RAVI MGR 1000 120
160 RAJU MGR 4000 121
161 CHAN MGR 1000 122
6 rows selected.
1.create table in scott and give grant to apps then create synonym in app
create table emp3(empno number(10),ename varchar2(10),job varchar2(10),sal number(10,2))
SQL> /
Table created.
SQL> grant all on emp3 to apps;
Grant succeeded.
SQL> conn apps/apps@prod
Connected.
SQL> create public synonym emp3 for scott.emp3;
Synonym created.
SQL> desc emp3;
Name Null? Type
----------------------------------------------------- -------- ------------------------------------
EMPNO NUMBER(10)
ENAME VARCHAR2(10)
JOB VARCHAR2(10)
SAL NUMBER(10,2)
2.data file
3.control file
4.RUN CMD THEN GIVE COMMAND AS
D:\ORACLE\PRODDB\8.1.7\BIN> SQLLDR APPS/APPS@PROD
CONTROL =D:\DATA\EMP3.CTL
5.GOTO SQL PROMPT THEN VIEW THE OUT PUT:
SQL> SELECT * FROM EMP3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
100 'smith' 'mgr' 7000
200 'ramu' 'clerk' 4000
300 'raju' 'act' 6000
SQL>
Multiple Data Files Into Single Database table using single control file
1.Create second data file:
111,'RAVI','MGR',7000
222,'KIRAN','CLERK',4000
333,'CHANDRA','ASTMGR',10000
save this as EMP4.DAT in same directory
2.Goto control file then assign this file as second infile to control file
controlfile:
load data
infile 'd:\data\emp3.dat'
infile 'd:\data\EMP4.dat'
insert into table emp3
fields terminated by ','
(empno
,ename
,job
,sal
)
3.Again run cmd as above
4.goto backend view data
SQL> select * from emp3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
111 'RAVI' 'MGR' 7000
222 'KIRAN' 'CLERK' 4000
333 'CHANDRA' 'ASTMGR' 10000
100 'smith' 'mgr' 7000
200 'ramu' 'clerk' 4000
300 'raju' 'act' 6000
6 rows selected.
Control file using sql functions
1) Assign the sql functions to the columns in Control file
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno "S1.NEXTVAL",
ename POSITION(4:7) "UPPER(:ENAME)",
job POSITION(8:10) "INITCAP(:JOB)",
sal POSITION(11:14) "NVL(:SAL*10,0)"
)
into table emp4 when projno!=' '
(
empno "S1.NEXTVAL",
ename POSITION(4:7) "UPPER(:ENAME)",
job POSITION(8:10) "INITCAP(:JOB)",
sal POSITION(11:14) "NVL(:SAL*10,0)",
projno POSITION(15:17)
)
2
AGAIN RUN CMD:
2. THEN VIEW THE DATA IN BACK END AS:
SQL> SELECT * FROM EMP3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
192 RAVI Mgr 70000
193 RAJU Mgr 40000
194 CHAN Mgr 10000
186 RAVI Mgr 70000
187 RAJU Mgr 40000
188 CHAN Mgr 10000
6 rows selected.
SQL> SELECT * FROM EMP4;
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
195 RAVI Mgr 70000 120
196 RAJU Mgr 40000 121
197 CHAN Mgr 10000 122
189 RAVI Mgr 70000 120
190 RAJU Mgr 40000 121
191 CHAN Mgr 10000 122
6 rows selected.
Using where clause in control file to update data into multiple tables
Multiple data files and Multiple tables
1.Create 2 tables and 2 data files
first is emp3 which is already created
Now created second table
CREATE TABLE EMP4 AS SELECT * FROM EMP3 WHERE 1=2
1.1ALTER TABLE EMP4 ADD PROJNO NUMBER; /*for additing additional column for secondtable */
SQL> DESC EMP4;
Name Null? Type
----------------------------------------------------- -------- ----------------------
EMPNO NUMBER(10)
ENAME VARCHAR2(10)
JOB VARCHAR2(10)
SAL NUMBER(10,2)
PROJNO NUMBER
SQL> GRANT ALL ON EMP4 TO APPS;
Grant succeeded.
SQL> CONN APPS/APPS@PROD
Connected.
SQL> CREATE PUBLIC SYNONYM EMP4 FOR SCOTT.EMP4;
Synonym created.
2.create datafile as emp3
111RAVIMGR7000120
222RAJUMGR4000121
333CHANMGR1000122
3.create data file as emp4
111RAVIMGR7000120
222RAJUMGR4000121
333CHANMGR1000122
4.create control file as
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno POSITION(1:3),
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14)
)
into table emp4 when projno!=' '
(empno POSITION(1:3),
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14),
projno POSITION(15:17)
)
save;
5.run cmd as usual
6.view the output in backend
SQL> select * from emp3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
111 RAVI MGR 7000
222 RAJU MGR 4000
333 CHAN MGR 1000
111 RAVI MGR 7000
222 RAJU MGR 4000
333 CHAN MGR 1000
6 rows selected.
SQL> select * from emp4;
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
111 RAVI MGR 7000 120
222 RAJU MGR 4000 121
333 CHAN MGR 1000 122
111 RAVI MGR 7000 120
222 RAJU MGR 4000 121
333 CHAN MGR 1000 122
6 rows selected.
Using commit in control files for each 10 records
1 .we will create a sequence as s1
SQL> CONN SCOTT/TIGER@PROD
Connected.
SQL> CREATE SEQUENCE S1 INCREMENT BY 1 START WITH 100;
Sequence created.
SQL> conn apps/apps@prod
Connected.
2.then we will create control file as
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14)
)
into table emp4 when projno!=' '
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14),
projno POSITION(15:17)
)
then save;
4.then run as usual.
5 .view the data from backend as
SQL> /
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
106 RAVI MGR 7000
107 RAJU MGR 4000
108 CHAN MGR 1000
100 RAVI MGR 7000
101 RAJU MGR 4000
102 CHAN MGR 1000
6 rows selected.
SQL> ed
Wrote file afiedt.buf
1* select * from emp4
SQL> /
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
109 RAVI MGR 7000 120
110 RAJU MGR 4000 121
111 CHAN MGR 1000 122
103 RAVI MGR 7000 120
104 RAJU MGR 4000 121
105 CHAN MGR 1000 122
6 rows selected
To Create Commit Statement in cmd Prompt
GOTO RUN CMD AND GIVE COMMAND AS TO FOR EVERY 2 RECORDS
TO SKIP RECORDS FROM LOADING USING SKIP KEYWORDS IN CONTROL FILE
GO TO RUN CMD:THEN GIVE THE COMMAND AS:
Goto backend and view the data:
SQL> SELECT * FROM EMP3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
148 CHAN MGR 1000
TO SKIP COLUMNS IN CONTROL FILES USING FILLER KEYWORD
Use the FILLER keyword in control files as:
load data
infile 'D:\DATA\emp3.dat'
infile 'D:\DATA\EMP4.dat'
insert
into table emp3
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job filler,
sal POSITION(11:14)
)
into table emp4 when projno!=' '
(
empno "S1.NEXTVAL",
ename POSITION(4:7),
job POSITION(8:10),
sal POSITION(11:14),
projno POSITION(15:17)
)
Then goto run cmd give the command as usual:
Then view the data in backend :
SQL> select * from emp3;
EMPNO ENAME JOB SAL
---------- ---------- ---------- ----------
150 RAVI 7000
151 RAJU 4000
152 CHAN 1000
156 RAVI 7000
157 RAJU 4000
158 CHAN 1000
6 rows selected.
SQL> select * from emp4;
EMPNO ENAME JOB SAL PROJNO
---------- ---------- ---------- ---------- ----------
153 RAVI MGR 7000 120
154 RAJU MGR 4000 121
155 CHAN MGR 1000 122
159 RAVI MGR 1000 120
160 RAJU MGR 4000 121
161 CHAN MGR 1000 122
6 rows selected.
Tuesday, April 28, 2015
Oracle Joins
Type of joins
-------------
(8i and Prior) Compliant
Joins
------------------------ -----------------
- Equijoin -
Cross Joins
- Non-Equijoin -
Natural Joins
- Outer Join -
Using Clause
- Self Join - Full or Two sided outer joins
-
Arbitrary join conditions for outer joins
1. Use a join to
query data from more than one table
SELECT table1.column, table2.column
FROM table1
[CROSS JOIN table2]|
[NATURAL JOIN table2] |
[JOIN table2 USING { column_name } ]
|
[JOIN table2 ON (table1.column_name=
table2.column_name)] |
[LEFT | RIGHT | FULL OUTER JOIN
table2 ON (table1.column_name = table2.column_name ) ];
2. Eg Cross
join:
SELECT ename,dname
FROM emp
CROSS JOIN DEPT;
3. NATURAL JOIN
---------------
- NATURAL JOIN
clause is based on all columns in the two tables that have the same name.
- It selects
rows from the two tables that have equal values in all matched columns
- If the columns
having the same names have different data types , an error is returned
In oracle 9i it
is possible to let the join be completed automatically based on columns in the
two tables which
have matching data types and names using the keywords NATURAL JOIN.
Eg: SELECT deptno,dname,ename,empno
FROM DEPT
NATURAL JOIN EMP
OR
SELECT deptno,dname,empno,ename
FROM EMP , DEPT
WHERE EMP.DEPTNO= DEPT.DEPTNO
Natural Joins
with WHERE clause
Additional restrictions on a natural
join are implemented by using a WHERE clause. The
example
SELECT
deptno,dname,ename,sal
FROM DEPT
NATURAL JOIN emp
WHERE deptno IN
(20,30)
4. NATURAL JOINS
WITH THE USING CLAUSE
---------------------------------------
- If several
columns have the same names but the data types do not match, The NATURAL JOIN
clause can be
modified with the USING clause to specify the columns that should be used for
an equijoin
- Use the USING
clause to match only one column when more thatn one column matches
- Do not use
table name or alias in the referenced columns
- The NATURAL
JOIN and USING clauses are mutually exclusive.
- The columns
referenced in the USING clause should not have a qualifier (table name or alias)
anywhere in the
SQL statement
SELECT
E.ENAME,D.DNAME
FROM EMP E JOIN
DEPT D USING (Deptno)
WHERE Deptno=30;
error coz we can
use alias or depts refered in join in either select or where clause
SELECT
E.ENAME,D.DNAME
FORM EMP E JOIN
DEPT D
USING (DEPTNO);
or
SELECT ENAME,DNAME
FORM EMP , DEPT
WHERE
EMP.DEPTNO=DEPT.DEPTNO
5. CREATING
JOINS WITH THE ON CLAUSE
--------------------------------------
- The join
condition for the natural join is basically an equi join of all columns with the
same
name
- To specify
arbitrary conditions or specify columns to join, the ON clause is used.
- The ON clause
makes code easy to understand
Eg
SQL> SELECT
E.ENAME,E.EMPNO,D.DNAME
2 FROM EMP E
3 JOIN DEPT D
4 USING (DEPTNO);
or
SQL> ed
1 SELECT ENAME,DNAME
2 FROM EMP
3 JOIN DEPT
4* USING (DEPTNO)
THREE WAY JOINS
WITH THE ON CLAUSE
----------------------------------
SELECT
EMPNO,ENAME,DNAME,SALGRADE
FROM EMP E
JOIN DEPT D
ON D.DEPTNO =
E.DEPTNO
JOIN DEPT1 D1
ON
D1.DEPTNO=E.DEPTNO
JOINS COMPARING
SQL to oracle syntax
----------------------------------------------------
ORACLE SQL
1999
---------------------------------------------------
EQUI-JOIN NATURAL/INNER JOIN
OUTER-JOIN LEFT OUTER
JOIN
SELF-JOIN JOIN ON
NON-EQUI-JOIN JOIN USING
CARTESIAN
PRODUCT CROSS JOIN
---------------------------------------------------
6. LEFT OUTER
JOIN
-------------------
SELECT
E.ENAME,E.DEPTNO,D.DNAME
FROM EMP E
LEFT OUTER JOIN DEPT D-> (+) will on this
table
ON (E.DEPTNO=D.DEPTNO)
OR
1
SELECT E.ENAME,E.DEPTNO,D.DNAME
2 FROM
EMP E,DEPT D
3* WHERE E.DEPTNO=D.DEPTNO(+)
OR
1
SELECT E.ENAME,E.DEPTNO,D.DNAME
2 FROM
EMP E,DEPT D
3* WHERE D.DEPTNO(+)=E.DEPTNO
7. RIGHT OUTER
JOIN:
---------------------
SELECT E.ENAME,E.DEPTNO,D.DNAME
FROM EMP E->(+) will b on this table
RIGHT OUTER JOIN DEPT D
ON(E.DEPTNO=D.DEPTNO)
or
1
SELECT E.ENAME,E.DEPTNO,D.DNAME
2 FROM
EMP E,DEPT D
3* WHERE D.DEPTNO=E.DEPTNO(+)
SQL> /
OUTER-JOIN:
-------------
-> To join n
tables together, you need a minimum of n-1 join conditions. This rule may not
apply if your
table has a concatenated primary key, in which case more than one column
is required to
uniquely identify each row.
-> The operator
is a plus sign enclosed in brackets and "it is placed on the side of the
join
that is
deficient in information" ie OUTER JOIN
This operator
has the effect of creating one or more null rows, to which one or more row from
the nondeficient
table can be joined.
Table.column =
is the condition that joins the tables together
table.column(+) is the outer join symbol, which can be placed
on either side of the where
clause condition
but not on both sides. place the outer join symbol follwing the name of the
column in the
table without the matching rows.
- the outer join
operator can appear on only one side of the expression the side that has
information
missing. It returns those rows from one table that have no direct match in the
other table.
- A condition
involving an outer join cannot use the IN operator or b linked to another condition
by the OR operator.
Eg: SELECT
E.ENAME,E.EMPNO,E.MGR,M.EMPNO,M.ENAME
FROM EMP E,EMP M
WHERE
E.MGR=M.EMPNO(+)
--The above
query gives all the employee details whose empno = mgrno which implies they are
--managers and
we want the details of all employee (empno) who have mgr no or not ie whether
-- that empno
has mgr or not it displays all the empno's and if any empno doesnt have mgr
then
-- implies that
employee doesnt have manager like the empno=7839 ename =KING
8. FULL OUTER
JOIN:
--------------------
SELECT
E.ENAME,E.DEPTNO,D.DNAME
FROM EMP E
FULL OUTER JOIN
DEPT D
ON
(E.DEPTNO=D.DEPTNO)
Sunday, April 26, 2015
FlexField Concepts
OVERVIEW OF FLEXFIELD CONCEPTS
A flexfield is a field made up of sub-fields, or segments. A flexfield appears on your form as a pop-up window that contains a prompt for each segment. Each segment has a name and a set of valid values. There are two types of flexfields: key flexfields and descriptive flexfields.
BASIC FLEXFIELD CONCEPTS
Segment - A segment is a single sub-field within a flexfield. You define the appearance and meaning of individual segments when customizing a flexfield. A segment is represented in your database as a single table column.
For a key flexfield, a segment usually describes a particular characteristic of the entity identified by the flexfield. For example, you can have a key flex field that stores part numbers. The key flexfield can contain the part number PAD-YEL-NR-8 1/2x14, which represents a yellow, narrow ruled, 8 1/2" x 14" note pad. Each section in the part number, separated by a hyphen, describes a characteristic of the part. The first segment describes the object, a note pad, the second segment describes the color of the object, yellow, and so on.
Note that we also refer to the fields in a descriptive flexfield pop-up window as segments even though they do not necessarily make up meaningful codes like the segments in key flexfields. However, they do often describe a particular characteristic of the entity identified elsewhere on the form you are using.
Values, Validation and Value Sets - Your end user enters a segment value into a segment while using an application. Generally, the flexfield validates each segment against a set of valid values (a "value set") that are usually predefined. To "validate a segment" means that the flexfield compares the value a user enters in the segment against the values in the value set for that segment.
You can set up your flexfield so that it automatically validates segment values your end user enters against a table of valid values. If your end user enters an invalid segment value, a list of valid values appears automatically so that the user can choose a valid value. You can think of a value set as a "container" for your values. You choose what types of values can fit into your value set: their length, format, and so on.
A segment is usually validated, and usually each segment in a given flexfield uses a different value set. You can assign a single value set to more than one segment, and you can even share value sets among different flexfields. For most value sets, when you enter values into a flexfield segment, you can enter only values that already exist in the value set assigned to the segment.
Structure - A flexfield structure is a specific configuration of segments. If you add or remove segments, or rearrange the order of segments in a flexfield, you get a different structure.
You can define multiple segment structures for the same flexfield (if that flexfield has been built to support more than one structure). Your flexfield can display different prompts and fields for different end users based on a data condition in your form or application data. Both key and descriptive flexfields may allow more than one structure.
In some applications, different users may need a different arrangement of the segments in a flexfield (key or descriptive). Or, you might want different segments in a flexfield depending on, for example, the value of another form or database field.
Your Oracle General Ledger application, for example, provides different Accounting Flexfield (Chart of Accounts) structures for users of different sets of books. The Oracle General Ledger application determines which flexfield structure to use based on the value of the GL Set of Books Name user profile option.
A flexfield is a field made up of sub-fields, or segments. A flexfield appears on your form as a pop-up window that contains a prompt for each segment. Each segment has a name and a set of valid values. There are two types of flexfields: key flexfields and descriptive flexfields.
BASIC FLEXFIELD CONCEPTS
Segment - A segment is a single sub-field within a flexfield. You define the appearance and meaning of individual segments when customizing a flexfield. A segment is represented in your database as a single table column.
For a key flexfield, a segment usually describes a particular characteristic of the entity identified by the flexfield. For example, you can have a key flex field that stores part numbers. The key flexfield can contain the part number PAD-YEL-NR-8 1/2x14, which represents a yellow, narrow ruled, 8 1/2" x 14" note pad. Each section in the part number, separated by a hyphen, describes a characteristic of the part. The first segment describes the object, a note pad, the second segment describes the color of the object, yellow, and so on.
Note that we also refer to the fields in a descriptive flexfield pop-up window as segments even though they do not necessarily make up meaningful codes like the segments in key flexfields. However, they do often describe a particular characteristic of the entity identified elsewhere on the form you are using.
Values, Validation and Value Sets - Your end user enters a segment value into a segment while using an application. Generally, the flexfield validates each segment against a set of valid values (a "value set") that are usually predefined. To "validate a segment" means that the flexfield compares the value a user enters in the segment against the values in the value set for that segment.
You can set up your flexfield so that it automatically validates segment values your end user enters against a table of valid values. If your end user enters an invalid segment value, a list of valid values appears automatically so that the user can choose a valid value. You can think of a value set as a "container" for your values. You choose what types of values can fit into your value set: their length, format, and so on.
A segment is usually validated, and usually each segment in a given flexfield uses a different value set. You can assign a single value set to more than one segment, and you can even share value sets among different flexfields. For most value sets, when you enter values into a flexfield segment, you can enter only values that already exist in the value set assigned to the segment.
Structure - A flexfield structure is a specific configuration of segments. If you add or remove segments, or rearrange the order of segments in a flexfield, you get a different structure.
You can define multiple segment structures for the same flexfield (if that flexfield has been built to support more than one structure). Your flexfield can display different prompts and fields for different end users based on a data condition in your form or application data. Both key and descriptive flexfields may allow more than one structure.
In some applications, different users may need a different arrangement of the segments in a flexfield (key or descriptive). Or, you might want different segments in a flexfield depending on, for example, the value of another form or database field.
Your Oracle General Ledger application, for example, provides different Accounting Flexfield (Chart of Accounts) structures for users of different sets of books. The Oracle General Ledger application determines which flexfield structure to use based on the value of the GL Set of Books Name user profile option.
Friday, April 24, 2015
SUBSTR INSTR
SUBSTR
Oracle/PLSQL: SUBSTR Function
This Oracle tutorial explains how to use the Oracle/PLSQL SUBSTR function with syntax and examples.
Description
The Oracle/PLSQL SUBSTR functions allow you to extract a substring from a string.
Syntax
The syntax for the SUBSTR function in Oracle/PLSQL is:
SUBSTR( string, start_position [, length ] )
Parameters or Arguments
string
The source string.
start_position
The starting position for extraction. The first position in the string is always 1.
length
Optional. It is the number of characters to extract. If this parameter is omitted, the SUBSTR function will return the entire string.
Note:
If start_position is 0, then the SUBSTR function treats start_position as 1 (ie: the first position in the string).
If start_position is a positive number, then the SUBSTR function starts from the beginning of the string.
If start_position is a negative number, then the SUBSTR function starts from the end of the string and counts backwards.
If length is a negative number, then the SUBSTR function will return a NULL value.
Applies To
The SUBSTR function can be used in the following versions of Oracle/PLSQL:
Oracle 12c, Oracle 11g, Oracle 10g, Oracle 9i, Oracle 8i
Example
Let's look at some Oracle SUBSTR function examples and explore how to use the SUBSTR function in Oracle/PLSQL.
For example:
SUBSTR('This is a test', 6, 2)
Write Output
SUBSTR('This is a test', 6)
Write Output
SUBSTR('Chandra Sekhar', 1, 4)
Write Output
SUBSTR('Chadra Sekhar', -3, 3)
Write Output
SUBSTR('Chandra Sekhar', -6, 3)
Write ouput
SUBSTR('Chandra Sekhar', -8, 2)
Result: 'On'
INSTR
The Oracle INSTR function searches inside a string for a substring. The Oracle INSTR function works in a way similar to the SUBSTR function, but INSTR returns an integer number indicating the position of the substring within the string, rather than returning the substring itself.
Note: For more complex string handling functions, you can make use of Regular Expressions by using the extended version of the INSTR function named REGEXPR_INSTR.
Example Syntax:
INSTR( source_string, substring [, start_position [, occurrence ] ] )
Source_string is the string to be searched.
substring is the character string to be searched for inside of source_string.
Start_position is an optional argument. It is an integer value that tells Oracle where to start searching in the source_string. If the start_position is negative, then Oracle counts back that number of characters from the end of the source_string and then searches backwards from that position. If omitted, this defaults to 1.
Occurrence is an integer indicating which occurrence of substring Oracle should search for. That is, should INSTR return the first matching substring, the second matching substring, etc. This argument is optional. If omitted, it defaults to 1.
If the sub string is not found in source string, the Oracle INSTR function will return 0.
INSTR('ABC-DC-F','-',2) output 7 (2nd occurence of '-')
Question on Instr/Sub string
There is a path in obiee where it is showing as /shared/financials/. In this string, want to get the value after second special character ('/') to before third special character ('/').
That means i should get the value "financials".
Solution
select substr(:a,instr(:a,'/',1,2)+1, length (:a)) from dual
Notes On Date Data Type
YEAR Year, spelled out
YYYY 4-digit year
YYY
YY
Y Last 3, 2, or 1 digit(s) of year.
IYY
IY
I Last 3, 2, or 1 digit(s) of ISO year.
IYYY 4-digit year based on the ISO standard
Q Quarter of year (1, 2, 3, 4; JAN-MAR = 1).
MM Month (01-12; JAN = 01).
MON Abbreviated name of month.
MONTH Name of month, padded with blanks to length of 9 characters.
RM Roman numeral month (I-XII; JAN = I).
WW Week of year (1-53) where week 1 starts on the first day of the year and continues to the seventh day of the year.
W Week of month (1-5) where week 1 starts on the first day of the month and ends on the seventh.
IW Week of year (1-52 or 1-53) based on the ISO standard.
D Day of week (1-7).
DAY Name of day.
DD Day of month (1-31).
DDD Day of year (1-366).
DY Abbreviated name of day.
J Julian day; the number of days since January 1, 4712 BC.
HH Hour of day (1-12).
HH12 Hour of day (1-12).
HH24 Hour of day (0-23).
MI Minute (0-59).
SS Second (0-59).
SSSSS Seconds past midnight (0-86399).
FF Fractional seconds.
ex:
SELECT TO_CHAR(SYSDATE,'MON') FROM DUAL
It will return Month is this Format JAN,FEB,MAR,,,
Note while comparing need to TRUNC(SYSDATE) otherwise data has Time stamp also
SQL functions
MIN
SELECT MIN(aggregate_expression)
FROM tables
WHERE conditions;
ex:
SELECT min(sal)
FROM emp
it will return Minimum salary of the Employee table
MaX
SELECT MAX(aggregate_expression)
FROM tables
WHERE conditions;
ex:
SELECT MAX(sal)
FROM emp
it will return Maximum salary of the Employee table
AVG
SELECT AVG(aggregate_expression)
FROM tables
WHERE conditions;
Example
SELECT AVG(sal)
FROM emp
it will return Average salary of the Employees table
COUNT
Example
SELECT count(*)
FROM emp
it will return no of employee of the Employees table
Oracle/PLSQL: SUBSTR Function
This Oracle tutorial explains how to use the Oracle/PLSQL SUBSTR function with syntax and examples.
Description
The Oracle/PLSQL SUBSTR functions allow you to extract a substring from a string.
Syntax
The syntax for the SUBSTR function in Oracle/PLSQL is:
SUBSTR( string, start_position [, length ] )
Parameters or Arguments
string
The source string.
start_position
The starting position for extraction. The first position in the string is always 1.
length
Optional. It is the number of characters to extract. If this parameter is omitted, the SUBSTR function will return the entire string.
Note:
If start_position is 0, then the SUBSTR function treats start_position as 1 (ie: the first position in the string).
If start_position is a positive number, then the SUBSTR function starts from the beginning of the string.
If start_position is a negative number, then the SUBSTR function starts from the end of the string and counts backwards.
If length is a negative number, then the SUBSTR function will return a NULL value.
Applies To
The SUBSTR function can be used in the following versions of Oracle/PLSQL:
Oracle 12c, Oracle 11g, Oracle 10g, Oracle 9i, Oracle 8i
Example
Let's look at some Oracle SUBSTR function examples and explore how to use the SUBSTR function in Oracle/PLSQL.
For example:
SUBSTR('This is a test', 6, 2)
Write Output
SUBSTR('This is a test', 6)
Write Output
SUBSTR('Chandra Sekhar', 1, 4)
Write Output
SUBSTR('Chadra Sekhar', -3, 3)
Write Output
SUBSTR('Chandra Sekhar', -6, 3)
Write ouput
SUBSTR('Chandra Sekhar', -8, 2)
Result: 'On'
INSTR
The Oracle INSTR function searches inside a string for a substring. The Oracle INSTR function works in a way similar to the SUBSTR function, but INSTR returns an integer number indicating the position of the substring within the string, rather than returning the substring itself.
Note: For more complex string handling functions, you can make use of Regular Expressions by using the extended version of the INSTR function named REGEXPR_INSTR.
Example Syntax:
INSTR( source_string, substring [, start_position [, occurrence ] ] )
Source_string is the string to be searched.
substring is the character string to be searched for inside of source_string.
Start_position is an optional argument. It is an integer value that tells Oracle where to start searching in the source_string. If the start_position is negative, then Oracle counts back that number of characters from the end of the source_string and then searches backwards from that position. If omitted, this defaults to 1.
Occurrence is an integer indicating which occurrence of substring Oracle should search for. That is, should INSTR return the first matching substring, the second matching substring, etc. This argument is optional. If omitted, it defaults to 1.
If the sub string is not found in source string, the Oracle INSTR function will return 0.
INSTR('ABC-DC-F','-',2) output 7 (2nd occurence of '-')
Question on Instr/Sub string
There is a path in obiee where it is showing as /shared/financials/. In this string, want to get the value after second special character ('/') to before third special character ('/').
That means i should get the value "financials".
Solution
select substr(:a,instr(:a,'/',1,2)+1,
Pass your string for variable you can get the desired results
Notes On Date Data Type
YEAR Year, spelled out
YYYY 4-digit year
YYY
YY
Y Last 3, 2, or 1 digit(s) of year.
IYY
IY
I Last 3, 2, or 1 digit(s) of ISO year.
IYYY 4-digit year based on the ISO standard
Q Quarter of year (1, 2, 3, 4; JAN-MAR = 1).
MM Month (01-12; JAN = 01).
MON Abbreviated name of month.
MONTH Name of month, padded with blanks to length of 9 characters.
RM Roman numeral month (I-XII; JAN = I).
WW Week of year (1-53) where week 1 starts on the first day of the year and continues to the seventh day of the year.
W Week of month (1-5) where week 1 starts on the first day of the month and ends on the seventh.
IW Week of year (1-52 or 1-53) based on the ISO standard.
D Day of week (1-7).
DAY Name of day.
DD Day of month (1-31).
DDD Day of year (1-366).
DY Abbreviated name of day.
J Julian day; the number of days since January 1, 4712 BC.
HH Hour of day (1-12).
HH12 Hour of day (1-12).
HH24 Hour of day (0-23).
MI Minute (0-59).
SS Second (0-59).
SSSSS Seconds past midnight (0-86399).
FF Fractional seconds.
ex:
SELECT TO_CHAR(SYSDATE,'MON') FROM DUAL
It will return Month is this Format JAN,FEB,MAR,,,
Note while comparing need to TRUNC(SYSDATE) otherwise data has Time stamp also
SQL functions
MIN
SELECT MIN(aggregate_expression)
FROM tables
WHERE conditions;
ex:
SELECT min(sal)
FROM emp
it will return Minimum salary of the Employee table
MaX
SELECT MAX(aggregate_expression)
FROM tables
WHERE conditions;
ex:
SELECT MAX(sal)
FROM emp
it will return Maximum salary of the Employee table
AVG
SELECT AVG(aggregate_expression)
FROM tables
WHERE conditions;
Example
SELECT AVG(sal)
FROM emp
it will return Average salary of the Employees table
COUNT
Example
SELECT count(*)
FROM emp
it will return no of employee of the Employees table
Wednesday, April 22, 2015
Oracle Dual Table
Oracle, DUAL is a table which is created with every installation of Oracle
The DUAL table's column, the column name, its datatype and even its value are not important. Technically it could be any datatype. DUAL exists just so we have a 1 row table we can reliably select from.
Don't EVER add rows to DUAL, fiddle with its column, or alter it in any way. If you do, you can expect some very strange and potentially destructive things to happen in your database, assuming the database doesn't just crash and burn completely
select sysdate from emp
1) select 1 from DUAL;
returns 1
2) select 1+2 from DUAL;
returns 3
3) select sysdate from DUAL;
returns system date of oracle database.
4) select `sql` from DUAL;
returns`sql`
5) select user from DUAL;
returns oracle user logged in.
6) select
(select empno from emp where empno = 10)
from DUAL;
returns 10
DUAL table can be used to test the SQL functions ( Both in-built and user defined functions)
7) select func_salary(10) from DUAL;
where func_salary is a user defined function returns a value when argument is 10.
8) select LOWER(`ORAclE`) from DUAL;
returns`oracle` where LOWER is a in-built SQL function.
Interview tips
If DUAL is supposed to have only one row, why is it called DUAL? Why not SINGLE?!
According to this old article on the history of Oracle’s DUAL table, DUAL was originally not meant to be seen itself but instead used inside a view that was expected to be queried. The idea was that you could do a JOIN to the DUAL table and create two rows in the result for every one row in your table. In that context, the name DUAL seemed fine.
Is it valid or not??
CREATE TABLE xxemp1
AS
SELECT * FROM DUAL
*Read*Explore*Succeed*
The DUAL table's column, the column name, its datatype and even its value are not important. Technically it could be any datatype. DUAL exists just so we have a 1 row table we can reliably select from.
Don't EVER add rows to DUAL, fiddle with its column, or alter it in any way. If you do, you can expect some very strange and potentially destructive things to happen in your database, assuming the database doesn't just crash and burn completely
select sysdate from emp
1) select 1 from DUAL;
returns 1
2) select 1+2 from DUAL;
returns 3
3) select sysdate from DUAL;
returns system date of oracle database.
4) select `sql` from DUAL;
returns`sql`
5) select user from DUAL;
returns oracle user logged in.
6) select
(select empno from emp where empno = 10)
from DUAL;
returns 10
DUAL table can be used to test the SQL functions ( Both in-built and user defined functions)
7) select func_salary(10) from DUAL;
where func_salary is a user defined function returns a value when argument is 10.
8) select LOWER(`ORAclE`) from DUAL;
returns`oracle` where LOWER is a in-built SQL function.
Interview tips
If DUAL is supposed to have only one row, why is it called DUAL? Why not SINGLE?!
According to this old article on the history of Oracle’s DUAL table, DUAL was originally not meant to be seen itself but instead used inside a view that was expected to be queried. The idea was that you could do a JOIN to the DUAL table and create two rows in the result for every one row in your table. In that context, the name DUAL seemed fine.
Is it valid or not??
CREATE TABLE xxemp1
AS
SELECT * FROM DUAL
*Read*Explore*Succeed*
Tuesday, April 21, 2015
Oracle Apps Basics
ERPs available in market
- SAP
- Oracle Applications
- People soft
- Siebel
- JD Edwards
Oracle
Applications are used to capture Business functionality information of the
organization.
- Instances
- Development - Development
- Development stage 1
- Development stage 2
- Testing - Testing
- Production – Client testing
Involved personalities of Oracle Applications
and their roles and responsibilities in brief
1)
DBA
– Database Administrator
a.
Installation
of Oracle Applications
b.
Applying
patches
c.
Maintaining
Multiple Instances
2)
Functional
Consultant
a.
Interaction
with the client
b.
Gathering
the requirements for development / customization
c.
About
oracle applications what available and what wasn’t available.
d.
Example
invoice form – fields - Or develop a
invoice form from scratch
e.
Preparation
of FDD (Functional Design Document)
3)
Technical
Consultant – Input FDD
a.
Go
through the FDD
b.
Prepare
TDD (Technical Design Document) – Logic, Tables, Procedures, Forms, Menus,
Packages – approval
c.
Development
of Component
d.
Test
the component
e.
Deliver
to the client
All these sessions will go trough the below
mentioned components
R I C
E -
Components for development 70%
- R - Reports - Reports 6i/10g
- I - Interfaces - Programs, SQL, PL/SQL
- C - Conversion - Programs, SQL, PL/SQL
- E - Extensions - Forms 6i/10g
Functions
Knowledge 30%
- Purchase Order Module
- Accounts Payable Module
- Order Management Module
- Inventory Module
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